Thread: Re: [Visualpython-users] Uniform scaling with gdisplay

Bru...@nc... writes:
>so I assume you are asking whether there is a way to permit autoscaling
>but force the scale factors to be equal. 
Yes, that's what I want. I hope that someone can give me a hint on how to
do it. In the minimal example below I want the spiral to keep its shape
fixed, still autoscaling when points fall outside the actual window.

BTW, running the example results in the following error message on my
computer:
VPython WARNING: errors in shader program:
It does not seem to be fatal but I would like to know what the reason is
and how to get rid of it.


from visual import *
import visual.graph as visualgraph
from time import *

spiralgraph=visualgraph.gdisplay(title='Spiral', ytitle='x', xtitle='y',
                              x=0, y=0, width=800,
height=800,foreground=visualgraph.color.black,
background=visualgraph.color.white)
spiralplot =
visualgraph.gdots(color=visualgraph.crayola.blue,display=spiralgraph)

for i in range(0,3600):
    t=pi*i/360
    spiralplot.plot(pos=(t*cos(t),t*sin(t)))
    sleep(0.001)
 

Even worse now:

Running the program below now results in the following error message:

Traceback (most recent call last):
  File "C:\pr\python\spiral.py", line 11
    spiralplot =
visualgraph.curve(color=visualgraph.crayola.magenta,display=spiralgraph)
  File "C:\Python32\lib\site-packages\vis\primitives.py", line 82, in
__init__
    if not _other: self.init_defaults(keywords)
  File "C:\Python32\lib\site-packages\vis\primitives.py", line 175, in
init_defaults
    self.material = self.display.material
AttributeError: 'gdisplay' object has no attribute 'material'





import visual.graph as visualgraph
from time import *
from math import *

spiralgraph=visualgraph.gdisplay(title='Spiral', ytitle='x', xtitle='y',
                                 x=0, y=0,
                                 width=800, height=800,
                                 foreground=visualgraph.color.black,
                                 background=visualgraph.color.white)
spiralplot =
visualgraph.curve(color=visualgraph.crayola.magenta,display=spiralgraph)
spiralplot.plot(pos=(-15,-15))
spiralplot.plot(pos=(15,-15))
spiralplot.plot(pos=(15,15))
spiralplot.plot(pos=(-15,15))
spiralplot.plot(pos=(-15,-15))
for i in range(0,3600):
    t=pi*i/360
    x=t*cos(t)
    y=t*sin(t)
    spiralplot.plot(pos=(x,y))
    sleep(0.001)




Poul Riis

What did you change? That is, what do you mean by "now"? Presumably
you didn't get such a very strange message before making some change.
Maybe you need to reinstall visual?

Bruce Sherwood

On Sun, Oct 14, 2012 at 12:32 PM, Poul Riis <Pou...@sk...> wrote:
> Even worse now:
>
> Running the program below now results in the following error message:
>
> Traceback (most recent call last):
>  File "C:\pr\python\spiral.py", line 11
>    spiralplot =
> visualgraph.curve(color=visualgraph.crayola.magenta,display=spiralgraph)
>  File "C:\Python32\lib\site-packages\vis\primitives.py", line 82, in
> __init__
>    if not _other: self.init_defaults(keywords)
>  File "C:\Python32\lib\site-packages\vis\primitives.py", line 175, in
> init_defaults
>    self.material = self.display.material
> AttributeError: 'gdisplay' object has no attribute 'material'
>
>
>
>
>
> import visual.graph as visualgraph
> from time import *
> from math import *
>
> spiralgraph=visualgraph.gdisplay(title='Spiral', ytitle='x', xtitle='y',
>                                 x=0, y=0,
>                                 width=800, height=800,
>                                 foreground=visualgraph.color.black,
>                                 background=visualgraph.color.white)
> spiralplot =
> visualgraph.curve(color=visualgraph.crayola.magenta,display=spiralgraph)
> spiralplot.plot(pos=(-15,-15))
> spiralplot.plot(pos=(15,-15))
> spiralplot.plot(pos=(15,15))
> spiralplot.plot(pos=(-15,15))
> spiralplot.plot(pos=(-15,-15))
> for i in range(0,3600):
>    t=pi*i/360
>    x=t*cos(t)
>    y=t*sin(t)
>    spiralplot.plot(pos=(x,y))
>    sleep(0.001)
>
>
>
>
> Poul Riis

Oh, yes, I'm sorry, I missed a 'g'  in gcurve!

Poul Riis



from time import *
from math import *
import visual.graph as visualgraph


spiralgraph=visualgraph.gdisplay(title='Spiral', ytitle='x', xtitle='y',
                                 x=0, y=0,
                                 width=800, height=800,
                                 foreground=visualgraph.color.black,
                                 background=visualgraph.color.white)
spiralplot =
visualgraph.curve(color=visualgraph.color.red,display=spiralgraph)
spiralplot.plot(pos=(-15,-15))
spiralplot.plot(pos=(15,-15))
spiralplot.plot(pos=(15,15))
spiralplot.plot(pos=(-15,15))
spiralplot.plot(pos=(-15,-15))

for i in range(0,3600):
    t=pi*i/360
    x=t*cos(t)
    y=t*sin(t)
    spiralplot.plot(pos=(x,y))
    sleep(0.001)